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由已知,设f(x)=(1+sinx)/(1+x²) -k
则k=∫[-1:1][(1+sinx)/(1+x²) -k]dx
=∫[-1:1][1/(1+x²) -k]dx
=(arctanx -kx)|[-1:1]
=π/2 -2k
3k=π/2
k=π/6
f(x)=(1+sinx)/(1+x²) - π/6
lim f(x)
x→∞
=lim [(1+sinx)/(1+x²) - π/6]
x→∞
=0- π/6
=-π/6
则k=∫[-1:1][(1+sinx)/(1+x²) -k]dx
=∫[-1:1][1/(1+x²) -k]dx
=(arctanx -kx)|[-1:1]
=π/2 -2k
3k=π/2
k=π/6
f(x)=(1+sinx)/(1+x²) - π/6
lim f(x)
x→∞
=lim [(1+sinx)/(1+x²) - π/6]
x→∞
=0- π/6
=-π/6
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