Question

已知y=3xy+x，求代数式2x+3xy-2y/x-2xy-y的值

Answer 1

已知x等于3xy加y，求代数式(x-2xy-y)分之(2x+3xy-2y)的值
x=3xy+y
x-y=3xy
所以
（2x+3xy-2y)/(x-2xy-y)
=[2(x-y)-3xy]/[(x-y)-2xy]
=(6xy-3xy)/(3xy-2xy)
=(3xy)/(xy)
=3