Question

计算要过程∫√（e^x-1)dx

Answer 1

用换元法,好象刚才给你做一道类似题目啊
令√（e^x-1)=t,x=ln(t+1),dx=dt/(t+1)
x=ln5,t=2,x=ln10,t=3
原式
=∫[2,3]t/(1+t)dt
=∫[2,3][1-1/(1+t)]dt
=[t-ln(1+t)][2,3]
=1-ln4+ln3