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分解因式:2x2+3xy+y2+7x+4y+13;m2+4mn+3n2+5m+13n+4;
2个回答
展开全部
是不是这样的:
2x2+3xy+y2+7x+4y+3
=(2x+y)(x+y)+3(2x+y)+(x+y)+3
=(2x+y)*(x+y+3)+(x+y+3)
=(x+y+3)(2x+y+1)
m2+4mn+3n2+5m+13n+4
=(m+n)(m+3n)+4(m+3n)+(m+n)+4
=(m+3n)(m+n+4)+(m+n+4)
=(m+n+4)(m+3n+1)
2x2+3xy+y2+7x+4y+3
=(2x+y)(x+y)+3(2x+y)+(x+y)+3
=(2x+y)*(x+y+3)+(x+y+3)
=(x+y+3)(2x+y+1)
m2+4mn+3n2+5m+13n+4
=(m+n)(m+3n)+4(m+3n)+(m+n)+4
=(m+3n)(m+n+4)+(m+n+4)
=(m+n+4)(m+3n+1)
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