linux 脚本 怎么把一个目录下的所有文件名放到一个数组中,求大神指教
尝试的脚本:cd$pathnamels$pathname>folderlistchmod774folderlistcatfolderlistt=0whilereadLIN...
尝试的脚本:
cd $pathname
ls $pathname > folderlist
chmod 774 folderlist
cat folderlist
t=0
while read LINE
do
folder_list[$t]=$LINE
t=`expr $t + 1`
done < $folderlist
错误提示:
line 14: folderlist: Permission denied
chmod: cannot access `folderlist': No such file or directory
cat: folderlist: No such file or directory
draft.sh: line 23: $folderlist: ambiguous redirect 展开
cd $pathname
ls $pathname > folderlist
chmod 774 folderlist
cat folderlist
t=0
while read LINE
do
folder_list[$t]=$LINE
t=`expr $t + 1`
done < $folderlist
错误提示:
line 14: folderlist: Permission denied
chmod: cannot access `folderlist': No such file or directory
cat: folderlist: No such file or directory
draft.sh: line 23: $folderlist: ambiguous redirect 展开
3个回答
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IFS=$(echo -en "携棚缺\n\b") #为和冲了处理文件名中的空格、TAB
cd $pathname
j=0
for i in `ls -1`
do
辩辩 folder_list[j]=$i
j=`expr $j + 1`
done
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cd $pathname
name=*
arr=${name[@]}
echo @arr
name=*
arr=${name[@]}
echo @arr
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declare -a FILE
FILE+=(*)
FILE+=(*)
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