Question

一道很简单的题目

分解因式：ax^(n+1)-ax^n-20ax^(n-1)

Answer 1

ax^(n+1)-ax^n-20ax^(n-1)
=ax^(n-1)(x的平方-x-20)
=ax^(n-1)(x-5)(x+4)

Answer 2

=ax^(n-1) * (x^2-x-20)=ax^(n-1) * (x-5) * (x+4)

Answer 3

ax^(n+1)-ax^n-20ax^(n-1)
=ax^(n-1) (x^2-x-20)
=ax^(n-1) (x-5)(x+4)