Question

求c语言大佬救急 感谢感谢！

输入10个互不相同的正整数（当输入相同的数或负数及零时程序必须能处理），并按输入顺序存储在一个一维数组中，将这10个数中所有高于平均值的数从大到小排序后输出。

Answer 1

#include <stdio.h>

int main() {

        int a[10],i;

        int j,t,n = 10;

        double avr = 0.0;

        for(i = 0; i < n; ++i) {

                scanf("%d",&t);

                if(t <= 0 ) {

                        --i;

                        printf("这个数小于零，请重新输入!!!\n");

                        continue;

                }

                for(j = 0; j <=i; ++j) {

                        if(t == a[j]) {

                                --i;

                                printf("数据重复，请重新输入!!!\n");

                                continue;

                        }

                }

                a[i] = t;

                avr += t;

        }

        avr /= n;

        for(i = 0; i < n - 1; ++i) {

                for(j = i + 1; j < n; ++j) {

                        if(a[i] < a[j]) {

                                t = a[i];

                                a[i] = a[j];

                                a[j] = t;

                        }

                }

        }

        printf("平均值为:%.2lf\n",avr);

        printf("大于平均数的数有:\n");

        for(i = 0; i < n; ++i)

        if(a[i] > avr) printf("%d ",a[i]);

        printf("\n\n");

        return 0;

}