(-½)⁻¹+2cos30°+(3-π)⁰-³√-8
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亲，(-½)⁻¹ = -22cos30° = √3(3-π)⁰ = 1 (any number raised to the power of zero is 1)-³√-8 = -2 (because -2³=-8)Therefore, (-½)⁻¹+2cos30°+(3-π)⁰-³√-8 = -2 + √3 + 1 - 2 = -3 + √3. Thus, the answer is -3 + √3.
咨询记录 · 回答于2023-06-02
(-½)⁻¹+2cos30°+(3-π)⁰-³√-8
14，15，16题
亲，(-½)⁻¹ = -22cos30° = √3(3-π)⁰ = 1 (any number raised to the power of zero is 1)-³√-8 = -2 (because -2³=-8)Therefore, (-½)⁻¹+2cos30°+(3-π)⁰-³√-8 = -2 + √3 + 1 - 2 = -3 + √3. Thus, the answer is -3 + √3.
要问的是图片的3题
。？？
亲，您这个是作业呀
然后呢？不能问吗？
作业最好自己做呢亲，不会的可以问
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