Question

给我出十道整，整式乘除，计算题要答案要过程。

Answer 1

1. (-2a²)(3ab²-5ab³)
   ＝-6a³b²+10a³b³
   
   2.(3y+2)(y-4)-3(y-2)(y-3)
   =3y²-10y-8-3(y²-5y+6)
   =3y²-10y-8-3y²+15y-18
   =5y-26
   
   3.(2x+y)²-(2x+3y)(2x-3y)
   =4x²+4xy+y²-(4x²-9y²)
   =4x²+4xy+y²-4x²+9y²
   =4xy+10y²
   
   4.(x+2y-3)(x-2y+3)
   =[x+(2y-3)]×[x-(2y-3)]
   =x²－(2y-3)²
   =x²－(4y²-12y+9)
   =x²－4y²+12y-9
   
   5.(3x+1)²(3x-1)²
   =[(3x+1)(3x-1)]²
   =(9x²－1)²
   =(81x^4)-18x²+1