Question

过程怎么算的？

过程怎么算的？答案是什么？

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Answer 1

这是求光年的长度吧？列式应该是：

Answer 2

|(a-1)/(a-2)| ≤ 1/2 -1/2 ≤(a-1)/(a-2) ≤ 1/2 (a-1)/(a-2) ≤ 1/2 (1) and -1/2 ≤(a-1)/(a-2) (2) from (1) (a-1)/(a-2) ≤ 1/2 [2(a-1) - (a-2)] /[2(a-2)] ≤0 a/[2(a-2)] ≤0 0≤a 2 (3) from (2) -1/2 ≤(a-1)/(a-2) [2(a-1)+(a-2) ]/[2(a-2)] ≥0 (3a-4)/[2(a-2)] ≥0 a>2 or a< 4/3 (4) (3) and (4) 0≤a 2 and "a>2 or a< 4/3" 4/3 4/3