Question

C#中，怎么“打开文件”和“保存文件”？加50分

用openfileDialog函数和SaveFileDialog 进行打开和保存；帮我举个实例。也可以发给我
raofeng466627538.q@qq.com详细一点

Answer 1

string resultFile = "";
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "D:\\Patch";
openFileDialog1.Filter = "All files (*.*)|*.*|txt files (*.txt)|*.txt";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
resultFile = openFileDialog1.FileName;

string resultFile = "";
SaveFileDialog saveFileDialog1 = new SaveFileDialog ();
saveFileDialog1.Title = "保存";
saveFileDialog1.Filter = "All files (*.*)|*.*|txt files (*.txt)|*.txt";
saveFileDialog1.FilterIndex = 2;
if(saveFileDialog1.ShowDialog() == DialogResult.OK)
resultFile =saveFileDialog1.FileName;

Answer 2

窗体上添加openfilediolog
选择一个button双击在其代码下编写
this .openFileDialog1.Showdialog();
或 openFIleDialog opfile=new OpenFileDialog();
opfile,ShowDialog();