Question

（X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以（X分之1+Y分之1）要有过程

Answer 1

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]
=[xy/(x+y)]×xy/(x+y)
=x²y²/(x+y)²

Answer 2

解原式=x+y分之x+2y乘于x+2y2y分之xy除于（xy分之y+xy分之x)
=x+y分之x+2y乘于x+2y分之xy乘于x+y分之xy
=(x+y)²分之x²y²

看我做的对不对，其实我也是初二的！

Answer 3

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]
=[xy/(x+y)]×xy/(x+y)
=x²y²/(x+y)²