Question

我的程序没语法错误但为何执行不出结果呢？我想用结构体输出5名学生信息，跪求答案！各位同仁拜托了！！！

#include<iostream>
using namespace std;
struct student
{
char name[9];
char num[6];
int score;
};
student s1[5];
void input(student s1[],int n)
{
int i,j;
cout<<"please enter the information of 5 students:"<<endl;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
cin>>s1[i].name[j];
cin>>s1[i].num[j];
cin>>s1[i].score;
}
}
}
void output(student s1[],int n)
{
int i,j;
cout<<"here is the information:"<<endl;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
cout<<s1[i].name[j]<<" "<<s1[i].num[j]<<" "<<s1[i].score<<endl;
}
}
}
void main()
{
int n=5;
input(s1,n);
output(s1,n);
}

Answer 1

C 中结构体就是类，所以可以枝哗有构造函数以及运算符重载，不过结构体默认的成员都是共有成员明困 我不是大牛^_^ 前激搭念两个是构造函数：第一个是默认构造函数

追问

还是不太明白!!!结构体默认的成员都是共有成员这个懂！

Answer 2

using namespace std;
struct student
{
char name[9];
char num[6];
int score;
};
student s1[5];
void input(student s1[],int n)
{
int i;//j多余 int i,j;
cout<<"please enter the information of 5 students:"基逗<<endl;
for(i=0;i<n;i++)
{
/*错 for(j=0;j<n;j++)
{
cin>>s1[i].name[j];
cin>>s1[i].num[j];
cin>>s1[i].score;
}*/
cin>早锋迟>s1[i].name;
cin>>s1[i].num;
cin>>s1[i].score;
}
}
void output(student s1[],int n)
{
int i;//j多余 int i,j;
cout<<"here is the information:"<<endl;
for(i=0;i<n;i++)
{
/*错 for(j=0;j<n;j++)
{
cout<<s1[i].name[j]<<"陆李 "<<s1[i].num[j]<<" "<<s1[i].score<<endl;
}*/
cout<<s1[i].name<<" "<<s1[i].num<<" "<<s1[i].score<<endl;
}
}
void main()
{
int n=5;
input(s1,n);
output(s1,n);
}