Question

问①丅数学题，急急急急急急！！！！

1.log^(1/2)^2+3log^(1/2)^8
2.3log^0.1^10-log^0.1^10^2

要步骤~~~~

Answer 1

1.log^(1/2)^2+3log^(1/2)^8
=log^(1/2)^[2*8^3]
=log^(1/2)^（2^10)
=log^(1/2)^[（1/2）^(-10)]
=-10
2. 3log^0.1^10-log^0.1^10^2
=log^0.1^(10^3/10^2)
=log^0.1^10
=log^0.1^[(0.1)^(-1)]
=-1

Answer 2

1.log^(1/2)^2+3log^(1/2)^8
=log^(1/2)^[2*8^3]
=log^(1/2)^（2^10)
=log^(1/2)^[（1/2）^(-10)]
=-10
2. 3log^0.1^10-log^0.1^10^2
=log^0.1^(10^3/10^2)
=log^0.1^10
=log^0.1^[(0.1)^(-1)]
=-1
这么做

Answer 3

【根据乘积法则】

【1】、log^(1/2)^2+3log^(1/2)^8
=log^(1/2)^[2*8^3]
=log^(1/2)^（2^10)
=log^(1/2)^[（1/2）^(-10)]
=-10
【2】、3log^0.1^10-log^0.1^10^2
=log^0.1^(10^3/10^2)
=log^0.1^10
=log^0.1^[(0.1)^(-1)]
=-1