Question

已知x^3+x^2+2x+1=0，求x^2+x+1的值

Answer 1

解：笑祥者稿 x³+x²+2x+1=0
x(x²+x+1)+x+1=0
(x²+x+1)=-(x+1)/碰嫌搏x
x²+x+1=-1-1/x

Answer 2

x³+2x²+2x+1=0
(x³森升燃+x²+x)+(x²此虚+x+1)=0
x(x²+x+1)+(x²+x+1)=0
(x²+x+1)(x+1)=0
x²+x+1=0或x=-1
x=-1时,x²+x+1=1-1+1=1
所以笑核x²+x+1=0或1