Question

已知函数F(x)=2sinxcos(x+派/6)-cos2x+m当X

(x)的最小值为-3，求实数M的值

Answer 1

F(x)=2sinxcos(x+π/6)-cos2x+m
= sin(2x+π/6) - sin(π/2-2x) + m - sin(π/6)
= 2*sin(2x - π/6)*cos(π/3) + m - sin(π/6)
= sin(2x - π/6) + m - 1/2
F(x)最小值为： m - 3/2；
m = -1.5