Question

有人能帮忙写个简单的按名字首字母排序python程序吗？

就是输入几个人的名字，按照姓的字母顺序排列，如果姓相同，就按名的字首字母排列，下面这个是范例：
How many names do you want to enter? 5
Enter name #1: Bill Clinton
Enter name #2: Michael Jackson
Enter name #3: Tony Blair
Enter name #4: Janet Jackson
Enter name #5: Oprah Winfrey
The names in order are:
Blair, Tony
Clinton, Bill
Jackson, Janet
Jackson, Michael
Winfrey, Oprah

Answer 1

#--encoding:utf-8--
def sortName(list):
#保存名字和第一个字母的map
nameMap ={}
#保存第一个字母并稍后进行排序
nameList =[]
for i in list:
nameMap[i[0]] = i
nameList.append(i[0])
nameList.sort()
for i in nameList:
print(nameMap[i])

if __name__ == '__main__':
list = ['Michael jack','Bill Cliton','Tony']
sortName(list)

运行结果：

Bill Cliton
Michael jack
Tony

汗 ，还有第二个字母，没看清。。不过原理一样的，map中key保存两个字母，就行了

修改后

#--encoding:utf-8--
def sortName(list):
#保存名字和第一个字母的map
nameMap ={}
#保存第一个字母并稍后进行排序
nameList =[]
for i in list:
len = i.find(' ')
str = i[0]
if(len > 0):
str = i[0]+i[len+1]
print str
nameMap[str] = i
nameList.append(str)
nameList.sort()
for i in nameList:
print(nameMap[i])

if __name__ == '__main__':
list = ['Michael jack','Michael cack','Michael zack','Bill Cliton','Tony']
sortName(list)
结果：
Bill Cliton
Michael cack
Michael jack
Michael zack
Tony

Answer 2

b=[ 'Bill Clinton','Michael Jackson','Tony Blair','Janet Jackson','Oprah Winfrey']
c=[i.split(' ') for i in b]
a=lambda x:(x[1][0],x[0][0])
c.sort(key=a)
for i in c:print(i[1],' ',i[0])