解x+1/(x-1)-4/(x^2-1)=1
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(x+1)/(x-1)-4/(x^2-1)=1
(x+1)/(x-1) - 4/(x^2-1) - 1 = 0
{ (x+1)^2/ - 4 - (x^2-1) } / {(x+1)(x-1) } = 0
{ x^2+2x+1 - 4 - x^2+1 } / {(x+1)(x-1) } = 0
2{ x - 2 } / {(x+1)(x-1) } = 0
x=2
(x+1)/(x-1) - 4/(x^2-1) - 1 = 0
{ (x+1)^2/ - 4 - (x^2-1) } / {(x+1)(x-1) } = 0
{ x^2+2x+1 - 4 - x^2+1 } / {(x+1)(x-1) } = 0
2{ x - 2 } / {(x+1)(x-1) } = 0
x=2
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