Question

y=sin(-3x+3.14/4)的单调递增区间是

y=sin(-3x+3.14/4)的单调递增区间是

Answer 1

y=sin(－3x＋π/4)=sin(3x＋3π/4)，增区间是2kπ－π/2≤3x－3π/4≤2kπ＋π/2，解得[2kπ/3＋π12，2kπ/3＋5π/12]。其中k是整数。

Answer 2

-3x+pi/4=2kpi+pi/2 x=-2kpi/3-pi/12
-3x+pi/4=2kpi+3pi/2 x=-2kpi/3-5pi/12
单调增区间[-2kpi/3-5pi/12,-2kpi/3-pi/12]

Answer 3

由题得 -π/2+2Kπ≤-3x+π/4≤π/2+2Kπ 解得增区间为[2kπ/3＋π12，2kπ/3＋5π/12]

Answer 4

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