Question

sum=1+3+5+7+(2n-1)的c语言程序

sum=1+3+5+7+(2n-1)的c语言程序

Answer 1

#include<stdio.h>
int main()
{
int sum,n,i;

scanf("%d",&n); //自己输入n

sum=0;

for(i=1;i<=2*n-1;i=i+2)

sum=sum+i; //计算1+.....+2*n-1的和;

printf("sum=%d\n",sum);

}

Answer 2

if(judge[0]==0xFF&&judge[1]==0xFE&&judge[6]==0xFD&&judge[7]==0xFC)
{

if(judge[5]==0x01)
{
hex_mod=16;
}
else
{
hex_mod=10;
}