Question

C语言综合作业：遍一个通讯录管理程序。通讯录应包含以下内容：序号，姓名，电话，地址等内容。具体要求如

1.显示所有已录入的通讯录。
2.实现新纪录的录入。
3.实现删除任何一条记录。
4.实现修改任意一条纪录。
5.可以根据姓名，电话或地址查询等相关信息。
6.系统的推出。

Answer 1

对数据的存储结构有要求吗？

#include <stdio.h>
#include <string.h>

const int MAX_NAME = 99;
const int MAX_PHONE = 27;
const int MAX_ADDR = 127;

typedef struct _PersonInfo
{
char name[MAX_NAME + 1];
char phone[MAX_PHONE + 1];
char addr[MAX_ADDR + 1];
}PersonInfo ;

const char *ID = "编号：";
const char *NAME = "姓名：";
const char *PHONE = "电话：";
const char *ADDR = "地址：";

const int MAX_NUM = 512;
PersonInfo g_piArry[MAX_NUM];

static int read_line ( FILE *fp, char *line, int max_length )
{
int i;
char ch;

/* initialize index to string character */
i = 0;

/* read to end of line, filling in characters in string up to its
maximum length, and ignoring the rest, if any */
for(;;)
{
/* read next character */
ch = fgetc(fp);

/* check for end of file error */
if ( ch == EOF )
return -1;

/* check for end of line */
if ( ch == '\n' )
{
/* terminate string and return */
line[i] = '\0';
return 0;
}

/* fill character in string if it is not already full*/
if ( i < max_length )
line[i++] = ch;
}

/* the program should never reach here */
return -1;
}

void menu_add();
void menu_print();
void menu_delete();
void menu_modify();
void menu_detail();

/* codes for menu */
#define PRINT_CODE 1
#define ADD_CODE 2
#define DEL_CODE 3
#define MOD_CODE 4
#define DETAIL_CODE 5
#define EXIT_CODE 6

int main(void)
{
memset(g_piArry, 0, sizeof(g_piArry));

for(;;)
{
int choice, result;
char line[301];

// FILE *fp1=fopen("input2","r");

/* print menu to standard error */
fprintf ( stderr, "\nOptions:\n" );
fprintf ( stderr, "%d: 显示所有已录入的通讯录\n", PRINT_CODE );
fprintf ( stderr, "%d: 录入新纪录\n", ADD_CODE );
fprintf ( stderr, "%d: 删除一条记录\n", DEL_CODE );
fprintf ( stderr, "%d: 修改一条纪录\n", MOD_CODE );
fprintf ( stderr, "%d: 根据姓名，电话或地址查询相关信息\n", DETAIL_CODE );
fprintf ( stderr, "%d: 退出系统\n", EXIT_CODE );
fprintf ( stderr, "\nEnter option: " );

if ( read_line ( stdin, line, 300 ) != 0 ) continue;
// read_line (fp1 , line, 300 ) ;

//printf("\n-----------%s-----------\n",line);

result = sscanf ( line, "%d", &choice );

if ( result != 1 )
{
fprintf ( stderr, "corrupted menu choice\n" );
continue;
}

switch ( choice )
{
case ADD_CODE: /* add book to database */
menu_add();
break;

case PRINT_CODE: /* get book details from database */
menu_print();
break;

case DEL_CODE: /* delete book from database */
menu_delete();
break;

case MOD_CODE: /* print database contents to screen
(standard output) */
menu_modify();
break;

case DETAIL_CODE: /* print tree to screen (standard output) */
menu_detail();
break;

/* exit */
case EXIT_CODE:
break;

default:
fprintf ( stderr, "illegal choice %d\n", choice );
break;
}

/* check for exit menu choice */
if ( choice == EXIT_CODE )
break;
}

return 0;
}

bool isdigit(char n)
{
if (n <= '9' && n >= '0')
{
return true;
}
else
{
return false;
}
}

int IsString(char *szBuff)
{
const int nLen = strlen(szBuff);

int nDigitCnt = 0;
int nPos = 0;
for (nPos = 0; nPos < nLen; nPos++)
{
if (isdigit(szBuff[nPos]))
{
nDigitCnt++;
}
}

if (nLen == nDigitCnt)
{
fprintf(stderr, "The words(%s) which you entered is digits, enter again!\n", szBuff);
return 0;
}

return 1;
}

/* trim the space of the words */
static int trim_space(char *p)
{
char *q = NULL;
if(*p != '\0')
{
q = p + strlen(p) - 1;
}
else
{
return -1;
}

for(; *q == ' '; q--);
*(q + 1) ='\0';

for(q = p; *q == ' '; q++);
strcpy(p,q);

return 0;
}

void print_node(PersonInfo *node, int n)
{
fprintf(stderr, "%s", ID);
printf("%d\n", n);

fprintf(stderr, "%s", NAME);
printf("%s\n", node->name);

fprintf(stderr, "%s", PHONE);
printf("%s\n", node->phone);

fprintf(stderr, "%s", ADDR);
printf("%s\n", node->addr);
}

void menu_add()
{
char name[MAX_NAME + 1] = {0};
char phone[MAX_PHONE + 1] = {0};
char addr[MAX_ADDR + 1] = {0};

int nId = 0;
do
{
fprintf(stderr, "%s", ID);
scanf("%d", &nId);
getchar();
}while(nId >= MAX_NUM && nId < 1);

int nLen = 0;
do
{
fprintf(stderr, "%s", NAME);
fgets(name, MAX_NAME, stdin);
nLen = strlen(name) - 1;
name[nLen] = '\0';
trim_space(name);
}while (!IsString(name));

fprintf(stderr, "%s", PHONE);
fgets(phone, MAX_PHONE, stdin);
nLen = strlen(phone) - 1;
phone[nLen] = '\0';

fprintf(stderr, "%s", ADDR);
fgets(addr, MAX_ADDR, stdin);
nLen = strlen(addr) - 1;
addr[nLen] = '\0';

nId = nId - 1;
PersonInfo *pi = &g_piArry[nId];
if (0 != strlen(pi->name))
{
int i = 0;
for (i = MAX_NUM; i > nId; i--)
{
memcpy(&g_piArry[i], &g_piArry[i - 1], sizeof(PersonInfo));
}
}

strcpy(pi->name, name);
strcpy(pi->phone, phone);
strcpy(pi->addr, addr);

return;
}

void menu_print()
{
int n = 0;
for (n = 0; n < MAX_NUM; n++)
{
if (0 != strlen(g_piArry[n].name))
{
print_node(&g_piArry[n], n + 1);
}
}
return;
}

void menu_delete()
{
int nId = 0;
do
{
fprintf(stderr, "%s", ID);
scanf("%d", &nId);
getchar();
}while(nId >= MAX_NUM && nId < 1);

PersonInfo *pi = &g_piArry[nId];

int i = 0;
for (i = nId - 1; i < MAX_NUM - 1; i++)
{
memcpy(&g_piArry[i], &g_piArry[i + 1], sizeof(PersonInfo));
}

fprintf(stderr, "删除成功(%s)", nId);
return ;
}

void menu_modify()
{
int nId = 0;
do
{
fprintf(stderr, "%s", ID);
scanf("%d", &nId);
getchar();
}while(nId >= MAX_NUM && nId < 1);

char name[MAX_NAME + 1] = {0};
char phone[MAX_PHONE + 1] = {0};
char addr[MAX_ADDR + 1] = {0};
int nLen = 0;

do
{
fprintf(stderr, "%s", NAME);
fgets(name, MAX_NAME, stdin);
nLen = strlen(name) - 1;
name[nLen] = '\0';
trim_space(name);
}while (!IsString(name));

fprintf(stderr, "%s", PHONE);
fgets(phone, MAX_PHONE, stdin);
nLen = strlen(phone) - 1;
phone[nLen] = '\0';

fprintf(stderr, "%s", ADDR);
fgets(addr, MAX_ADDR, stdin);
nLen = strlen(addr) - 1;
addr[nLen] = '\0';

nId = nId - 1;

PersonInfo *pi = &g_piArry[nId];
strcpy(pi->name, name);
strcpy(pi->phone, phone);
strcpy(pi->addr, addr);

return ;
}
void menu_detail()
{
int nId = 0;
do
{
fprintf(stderr, "%s", ID);
scanf("%d", &nId);
getchar();
}while(nId >= MAX_NUM && nId < 1);

print_node(&g_piArry[nId - 1], nId);

return;
}

追问

没有吧

追答

那就给分吧，我已经帮你搞定了。最多可以录入512个信息，你可以自己修改const int MAX_NUM = 512;

追问

删除记录的时候出了点问题，再改下。解决了马上采纳

追答

我现在没有时间

说你的那个删除有什么问题？

你得把错误描述一下吧！

追问

其他的要求都满足，不过在删除记录的时候，就终止运行了

追答

我测试过，没有问题。

把你的测试步骤给我看看

追问

我电脑里没装C++。今下午上机课后给你回复

追答

我的程序写的很简单，你自己看看。改改不就得了。。。

追问

删除记录的时候出问题了，一删除就程序终止。PS：我要是能改就不会到百度上来找人帮忙了

追答

把下面这个函数修改下：

void menu_delete()
{
int nId = 0;
do
{
fprintf(stderr, "%s", ID);
scanf("%d", &nId);
getchar();
}while(nId >= MAX_NUM && nId < 1);

PersonInfo *pi = &g_piArry[nId];

int i = 0;
for (i = nId - 1; i < MAX_NUM - 1; i++)
{
memcpy(&g_piArry[i], &g_piArry[i + 1], sizeof(PersonInfo));
}
memset(&g_piArry[i], 0x00, sizeof(PersonInfo));

fprintf(stderr, "删除成功(%d)", nId);
return ;
}

Answer 2

假设记录通讯录的表名为：TList
1. select * from TList
2. insert into TList(...) values(...)
3.delete from TList where ...
4.update TList set ... Where...
5.select * from TList Where name=? or name='' ....
界面用C++写，数据库就用SQL SERVER，简单方面。

Answer 3

需求再明确一下：
1.比如之前有3条记录，他们的序号为1、2、3，删除第二条记录之后，第三条记录的序号是仍然为3还是变为2？
2.删除和修改记录的时候分别根据什么进行删除或修改？序号？名字？还是其它？

追问

根据序号就行了

追答

我说的问题1呢？

Answer 4

比如之前有3条记录，他们的序号为1、2、3，删除第二条记录之后，第三条记录的序号是仍然为3还是变为2？

追问

应该变为2哦

Answer 5

你QQ或是邮箱多少，我把源文件发给你。

追问

550558136@qq.com 通讯录中没有序号，可不可以改下呢

追答

改下比较麻烦的.....现在很久没写C/C++了。