Question

解方程(x-1)/(x-2)-(x-3)/(x-a)=(x-2)/(x-3)-(x-4)/(x-5)

Answer 1

x-a?
a是另外的未知数？
是不是写错了
如果是4的话，解题如下

(x-1)/(x-2)-(x-3)/(x-a)=(x-2)/(x-3)-(x-4)/(x-5)
原式子1+1/(x-2)+1+1/(x-4)=1+1/(x-3)+1+1/(x-5)
1/(x-2)+1/(x-4)=1/(x-3)+1/(x-5)
1/(x-2)-1/(x-5)=1/(x-3)-1/(x-4)
(2x-7)/(x-2)(x-5)=(2x-7)/(x-3)(x-4)
2x-7=0
x=7/2

Answer 2

(1+1/x-2)-(1+1/x-4)=(1+1/x-3)-(1+1/x+5)
1/x-2-1/x-4=1/x-3-1/x-5
-2/x^-6x+8=-2/x^-8x+15
x^-6x+8=x^-8x+15
2x=7
x=7/2

Answer 3

X=7/2;

追问

要过程