Question

化简【sin^2(a+π)*cos(π+a)*cos(-a-2π)】/【tan(π+a)*sin^3(π/2+a)*sin(-a-2π)】=

Answer 1

[sin^2(a+π)cos(π+a)cos(-a-2π)]/[tan(π+a)sin^3(π/渣歼2+a)sin(-a-2π)]
=[sin^2a(-cosa)cosa]/如脊冲野衡[tana(-cos^3a)(-sina)]
=-sin^2acos^2a/[(sina/cosa)cos^3asina]
=-sin^2acos^2a/(sin^2acos^2a)
=-1

Answer 2

【辩棚sin^2(a+π)*cos(π+a)*cos(-a-2π)】/【tan(π+a)*sin^3(π/2+a)*sin(-a-2π)】携银则
=[sin^2a*(-cosa)*cos(2π+a)]/[tana*cos^3a*sin(2π+a)]
=-[sin^2a*cosa*cosa]/搏氏[sina*coa^2a*sina]
=-1