1个回答
展开全部
(y*根号x+x*根号y)/(xy-y2)-(x+根号xy+y)/(x根号x-y根悔渗号y)
=(y√x+x√y)/y(x-y)-((x+√xy+y)/((√x)^3-(√y)^3))
=(y√x+x√y)/y(x-y)-((x+√xy+y)/((√x-√y)((x+√xy+y)))
=(y√x+x√y)/(x-y)-(1/(√x-√y))
=((y√x+x√y)-y(√x+√y))/y(x-y)
=(y√x+x√y-y√x-y√y))/y(x-y)
=(x-y)√y/早闭y(x-y)
=√陆前裂y/y
=(y√x+x√y)/y(x-y)-((x+√xy+y)/((√x)^3-(√y)^3))
=(y√x+x√y)/y(x-y)-((x+√xy+y)/((√x-√y)((x+√xy+y)))
=(y√x+x√y)/(x-y)-(1/(√x-√y))
=((y√x+x√y)-y(√x+√y))/y(x-y)
=(y√x+x√y-y√x-y√y))/y(x-y)
=(x-y)√y/早闭y(x-y)
=√陆前裂y/y
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询