Question

2/3A的二次方减6A的三次方加5A-1/4+5A的三次方减1/2-4/3A的二次方简便过程？

Answer 1

(2/3)A^2-6A^3+5A-1/4+5A^3-1/2-(4/3)A^2
=[(2/3)A^2-(4/3)A^2]-(6A^3-5A^3)+5A-[(1/4)+(1/2)]
=(-2/3)A^2-A^3+5A-(3/4)。