Question

分解因式：2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²

Answer 1

2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
=2x(x-y)²(x-y)²-x²(x-y)²+xy(x-y)²
=(x-y)²[2x(x-y)²-x²+xy]
=(x-y)²[2x(x-y)²-x(x-y)]
=x(x-y)²(x-y)(2x-2y-1)

Answer 2

问题是不是提错了？

追问

呃，没就是换了种表达方式

追答

2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
=2x(x-y)²(x-y)²-x²(x-y)²+xy(x-y)²
=(x-y)²（2x^3-4x²y+2xy²)-(x-y)²x²+(x-y)²x
=(x-y)²(2x^3-4x²y+2xy²-x²+x)
好像只能这样了。