3个回答
展开全部
x=(√2-√吵腊培3)/升唯(√3+√2)
=(√2-√3)*(√3-√2)/((√3+√2)*(√3-√2))
=(-5+2√6)/(3-2)
=-5+2√6
y=(√3+√2)/局激(√3-√2)
=(√3+√2)*(√3+√2)/(√3-√2)*(√3+√2))
=(5+2√6)/(3-2)
=5+2√6
x*y=(√2-√3)/(√3+√2)*(√3+√2)/(√3-√2)
= -1
3x^2-5x*y+3y^2 =3(x^2-2x*y+y^2)+x*y
=3(x-y)^2+x*y
=3(-5+2√6-(5+2√6))^2+(-1)
=3(-5+2√6-5-2√6)^2+(-1)
=3(-10)^2-1
=300-1
=299
=(√2-√3)*(√3-√2)/((√3+√2)*(√3-√2))
=(-5+2√6)/(3-2)
=-5+2√6
y=(√3+√2)/局激(√3-√2)
=(√3+√2)*(√3+√2)/(√3-√2)*(√3+√2))
=(5+2√6)/(3-2)
=5+2√6
x*y=(√2-√3)/(√3+√2)*(√3+√2)/(√3-√2)
= -1
3x^2-5x*y+3y^2 =3(x^2-2x*y+y^2)+x*y
=3(x-y)^2+x*y
=3(-5+2√6-(5+2√6))^2+(-1)
=3(-5+2√6-5-2√6)^2+(-1)
=3(-10)^2-1
=300-1
=299
更多追问追答
追问
9到10排x*y为什么等余-1?你这片是抄的,我正在看,但还是请你解释下,谢谢!
追答
x*y=(√2-√3)/(√3+√2)*(√3+√2)/(√3-√2)
=1
展开全部
x=(根号3-根号2)/(根号3+根号猜腊2)=(√3-√2)(√3-√2)/(√3+√2)(√3-√2)=(√3-√2)²
y=(根号3+根号2)(根穗首滑号3-根号2),=(√3+√2)(√3+√2)/(√3-√2)(√3+√2)=(√3+√2)²
∴3x²-5xy+3y²
=3x²-6xy+3y²+xy
=3(x-y)²+xy
=3[(√3-√2)²-(√3+√2)²]+(√3-√2)(√3+√2)
=3(√3-√2+√芹迅3+√2)(√3-√2-√3-√2)+(3-2)
=3×2√3×(-2√2)+1
=-12√6+1
y=(根号3+根号2)(根穗首滑号3-根号2),=(√3+√2)(√3+√2)/(√3-√2)(√3+√2)=(√3+√2)²
∴3x²-5xy+3y²
=3x²-6xy+3y²+xy
=3(x-y)²+xy
=3[(√3-√2)²-(√3+√2)²]+(√3-√2)(√3+√2)
=3(√3-√2+√芹迅3+√2)(√3-√2-√3-√2)+(3-2)
=3×2√3×(-2√2)+1
=-12√6+1
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
x=(√3-√2)/(√3+√2),y=(√3+√2)/(√3-√2),
y-x=((√3+√激首弯2)*(√3+√2)-(√3-√2)*(√3-√2))/(3-2)=4√芹搏6
x=1/明闷y;
xy=1;
3x²-6xy+3y²+xy
=3(x-y)²+xy
=3*4*4*6+1=16*18+1=17*17=288
y-x=((√3+√激首弯2)*(√3+√2)-(√3-√2)*(√3-√2))/(3-2)=4√芹搏6
x=1/明闷y;
xy=1;
3x²-6xy+3y²+xy
=3(x-y)²+xy
=3*4*4*6+1=16*18+1=17*17=288
追问
呃,好像是对的,顺便帮我指下我上面的追问是什么回事?谢谢
追答
3x²-6xy+3y²+xy
=3(x-y)²+xy
=3*4*4*6+1=16*18+1=17*17=289
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询