Question

C语言的一个笑脸编程！求大神！

#include<stdio.h>
#include<conio.h>
struct move_point

{

int x,y;

int xv,yv;

}man;
int main()
{

gotoxy(man.x,man.y);

printf(" ");

man.x+=man.xv;

man.y+=man.yv;

gotoxy(man.x,man.y);

printf("%c\b", 2);

getch();
}
哪里错了呢。。下面显示有两个错误。。

Answer 1

#include <stdio.h>
#include <stdlib.h>

void main(void)
{
FILE *fp1 = NULL, *fp2=NULL;
char ch = ' ';
long n=0;

if ( ( fp1 = fopen("test.txt","r") ) == NULL )
{
printf("fail to open file \"test.txt\" press any key to exit!\n");
getchar();
exit(0);
}

if ( ( fp2 = fopen("result.txt","w") ) == NULL )
{
printf("fail to creat file \"test.txt\" press any key to exit!\n");
getchar();
exit(0);
}

fseek(fp1,-1L,SEEK_END);
n=ftell(fp1)+1;
ch=fgetc(fp1);
while ( n )
{
fputc(ch,fp2);
fseek(fp1,-2L,SEEK_CUR);
n--;
ch=fgetc(fp1);
}

fclose(fp1);
fclose(fp2);
printf("done!\n");
getchar();
}

VC++6.0上测试通过！注意文件test.txt要自己建立，并和这个可执行程序放在同一目录下！

Answer 2

gotoxy(man.x,man.y);没有定义啊
而且int main()，那么main应该返回一个值 比如 return 0；

Answer 3

#include<stdio.h>
#include<conio.h>

struct move_point

{

int x,y;

int xv,yv;

}man;

void main()
{

gotoxy(man.x,man.y);

printf(" ");

man.x+=man.xv;

man.y+=man.yv;

gotoxy(man.x,man.y);

printf("%c\b", 2);

getch();
}

特地下了一个TC，问题就出在 main()身上，必须有一个返回值。

Answer 4

void不需要返回什么