Question

asp里一字符串交替由字母和数字组成，如何把它分割存入数组？

谢谢啦！

Answer 1

/*
将一个字符串中的字母,数字字符分离出来,分别放入两个数组之中
*/
#include<stdio.h>

void main()
{
char *p,s[80],zm[80];
int sz[80];
int alpha,space,digit,other;
int i;
alpha=space=digit=other=0;
printf("input string: ");
gets(s);
for(p=s;*p!='\0';p++)
if( (*p>='a'&&*p<='z') || (*p>='A'&&*p<='Z') )
else if(*p==32) space++; //空格的ASCII码为32
else if(*p>='0' &&*p<='9' )
else other++;
printf("alpha:%d space:%d digit:%d other:%d\n",alpha,space,digit,other);
printf("字符数组内容为：");
for(i=0;i<alpha;i++)
{
printf("%c ",zm[i]);
}
printf("\n");
printf("数字数组内容为：");
for(i=0;i<digit;i++)
{
printf("%d ",sz[i]);
}
printf("\n");

}

Answer 2

for i=1 to len(trim(str1))
if mid(trim(str1),i,1)<>" " then
数组添加→ mid(trim(str1),i,1)
end if
next

Answer 3

<%
dim s,n1,t1
dim n()
dim t()
n1=0
t1=0
s="dsfdf123213rerr7867"
for i=1 to len(s)
if IsNumeric(mid(s,i,1))=true then
redim Preserve n(n1)
n(n1)=mid(s,i,1)
n1=n1+1
else
redim Preserve t(t1)
t(t1)=mid(s,i,1)
t1=t1+1
end if
next
response.write "数字数组："
for k=0 to ubound(n)
response.write n(k)
next
response.write "<br/>"
response.write "字符数组："
for j=0 to ubound(t)
response.write t(j)
next
%>

Answer 4

使用他里面的substring（）方法截取，然后再存

Answer 5

补充楼上

用IsNumeric（）函数判断第一个是否为数字