Question

解方程（要过程）

5【200020002x+300030003x乘（10-x）】=1000000000

Answer 1

5×[200020002x + (300030003x )×（10-x）]=1000000000
5×100010001×[2x+3x(10-x)]=1000000000
5×100010001×[2x+30x-3x² ]=1000000000
300030003x²-3200320032x+200000000=0
下面用求根公式算
计算Δ=3200320032² -4×300030003×200000000
=10242048307220481024-240024002400000000
=10002024304820481024
√Δ≈3162597714.6675612280472232717879
x₁≈(3200320032+3162597714.6675612280472232717879)/600060006
≈10.603802424832094588965529677024
x₂≈(3200320032-3162597714.6675612280472232717879)/600060006
≈0.06286424183457207770113698964317

Answer 2

5【200020002x+300030003x乘（10-x）】=1000000000
200020002x+300030003x乘（10-x）=200000000
300030003x²-3200320032x+200000000=0
用求根公式解得：x₁≈10.6 x₂≈0.06

Answer 3

解答如图

Answer 4

原式：5（200020002X+3000300030-300030003X）=1000000000
5（3000300030-100010001X）=1000000000
-500050005X=14001500150
X= -28.0002

Answer 5

化简，得 300030003 x^2 - 3200320032 x + 200000000 = 0
解得，x1=16 (33336667 - 根号1085289095575139)/100010001
x2=16 (33336667 +根号1085289095575139)/100010001
这是正确解法哦。