1个回答
展开全部
(1) parameter = 6x + 2h + 5x*2 = = 16x + 2h = 360, h = 180 - 8x cm
Let M be the middle point of QS, QM = 3x cm
It's easy to know that QRM is a right triagle, and RM = 4x cm (the sides are in the ratio of 3:4:5)
A = PT*PQ + (1/2)*QS*RM = 6x*(180 - 8x) + (1/2)*6x*4x = 1080x - 36x²
(2) A' = 1080 - 72x = 0, x= 15
(3) when x < 15, A' > 0; when x > 15, x < 0; the stationary value is a maximum
Let M be the middle point of QS, QM = 3x cm
It's easy to know that QRM is a right triagle, and RM = 4x cm (the sides are in the ratio of 3:4:5)
A = PT*PQ + (1/2)*QS*RM = 6x*(180 - 8x) + (1/2)*6x*4x = 1080x - 36x²
(2) A' = 1080 - 72x = 0, x= 15
(3) when x < 15, A' > 0; when x > 15, x < 0; the stationary value is a maximum
上海华然企业咨询
2024-10-28 广告
2024-10-28 广告
作为上海华然企业咨询有限公司的一员,我们深知大模型测试对于企业数字化转型与智能决策的重要性。在应对此类测试时,我们注重数据的精准性、算法的先进性及模型的适用性,确保大模型能够精准捕捉市场动态,高效分析企业数据,为管理层提供科学、前瞻的决策支...
点击进入详情页
本回答由上海华然企业咨询提供
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询