Question

在WINTC环境下用C语言编写一个实现两个整数加减乘除的程序,谢谢了！

Answer 1

#include<stdio.h>
#include<conio.h>
void main()
{
while(1)
{
int a=0,b=0,c=0,result,key;
char d;
printf("输入两个整数:\n");
scanf("%d",&a);
scanf("%d",&b);
printf("选择算法 '+','-','*','/' \n");
scanf(" %c",&d);
printf("输入计算结果:\n");
scanf("%d",&result);
switch(d)
{
case'+': c=a+b;break;
case'-': c=a-b;break;
case'*': c=a*b;break;
case'/': if(b>0) c=a/b;break;
}
if(result==c)
printf("回答正确!\n");
else printf("错误,正确答案是:%d\n",c);
printf("继续(y) 退出(n)\n");
key =getch();
if(key=='n' || key=='N')
break;
}
}

Answer 2

main()
{
int a,b,c;
scanf("%d%d",&a,&b);
{
(c=a+b);
printf("%d\n",c);
(c=a-b);
printf("%d\n",c);
(c=a*b);
printf("%d\n",c) ;
(c=a/b);
printf("%d\n",c) ;
}
getch();
}

我也刚学

Answer 3

#include "stdio.h"
main()
{
int x,y,a,b,c;
double d;
scanf("%d%d",&x,&y);
a=x+y;
b=x-y;
c=x*y;
d=(double)x/(double)y;
printf("x+y=%d x-y=%d x*y=%d x/y=%lf",a,b,c,d);
getch();
}

Answer 4

main()
{ int c,d,e;
float a,b,f;
scanf("%f%f",&a,&b);
c=a+b;
d=a-b;
e=a*b;
f=a/b;
printf("%d\n%d\n%d\n%f",c,d,e,f);
getch();
}
这种是最简洁，最方便的！！！