Question

java编程 找到10000之内的所有的回文数并输出。

Answer 1

public class TestNumber {
public static void main(String[] args) {
for (int i = 1; i <= 10000; i++) {
if (test(i)) {
System.out.println(i);
}
}
}

private static boolean test(int i) {
char c[] = String.valueOf(i).toCharArray();
for (int j = 0; j < c.length; j++) {
if (c[j] != c[c.length - j - 1]) {
return false;
}
}
return true;
}
}

Answer 2

package x;
import javax.swing.*;
public class X {
public static void main(String[] args) {
String s=(String)JOptionPane.showInputDialog(null,"请输入一个整数","输入对话框",JOptionPane.PLAIN_MESSAGE);
Long m,n=Long.parseLong(s);
System.out.println(n+"");
n=Math.abs(n);
m=n/10;
int i=1;
while(m>0){i=i*10;m=m/10;}
while(n>0)
{
if(n/i==n%10)
{n=n%i;n=n/10;i=i/100;}
else
break;
}
if(n==0)
System.out.println("回文数");
else
System.out.println("不是回文数");
}
}

看下这个吧！自己改改