|a-2022|+|b-1|=0,则a+b的值为多少?
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因为绝对值都是大于等于0的,现在它们的和是0,所以只有两个数都是0,所以 a=2022,b=1,a+b=2023
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由于绝对值是大于等于0的,a=2022,b=1,a+b的值为2023
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因为绝对值都是大于等于0的,已知等式和为0,所以只有它们都等于0才成立,所以a-2022=0,b-1=0。a=2022,b=1。a+b=2023
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如果^a+1+^b-1=0,则a2012+b2012是^u4dauquuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu答案:A+1=0,B-1=0,解A=-1,B=1,因此A2012+B2012=(-1)2012+12012=1+1=2。
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