高一数学化简题
(1/x^2+1/y^2)/[x^(-2/3)+y^(-2/3)]-(1/x^2-1/y^2)/[x^(-2/3)-y^(-2/3)]...
(1/x^2+1/y^2)/[x^(-2/3)+y^(-2/3)]-(1/x^2-1/y^2)/[x^(-2/3)-y^(-2/3)]
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(1/x^2+1/y^2)/[x^(-2/3)+y^(-2/3)]-(1/x^2-1/y^2)/[x^(-2/3)-y^(-2/3)]
=（x^2+y^2)(1/x^2y^2)[x^(-2/3)-y^(-2/3)]/[x^(-4/3)+y^(-4/3)]+(x^2-y^2)(1/x^2y^2)[x^(-2/3)+y^(-2/3)]/[x^(-4/3)-y^(-4/3)]
={（x^2+y^2)[x^(-2/3)-y^(-2/3)]+(x^2-y^2)[x^(-2/3)+y^(-2/3)]}/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=[2x^2x^(-2/3)-2y^2y^(-2/3)]/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=[2x^(4/3)-2y^(4/3)]/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=-2[x^(4/3)-y^(4/3)]/{x^(2/3)y^(2/3)[x^(4/3)-y^(4/3)]}
=-2/x^(2/3)y^(2/3)
=-2x^(-2/3)y^(-2/3)
=（x^2+y^2)(1/x^2y^2)[x^(-2/3)-y^(-2/3)]/[x^(-4/3)+y^(-4/3)]+(x^2-y^2)(1/x^2y^2)[x^(-2/3)+y^(-2/3)]/[x^(-4/3)-y^(-4/3)]
={（x^2+y^2)[x^(-2/3)-y^(-2/3)]+(x^2-y^2)[x^(-2/3)+y^(-2/3)]}/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=[2x^2x^(-2/3)-2y^2y^(-2/3)]/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=[2x^(4/3)-2y^(4/3)]/{x^2y^2[x^(-4/3)-y^(-4/3)]}
=-2[x^(4/3)-y^(4/3)]/{x^(2/3)y^(2/3)[x^(4/3)-y^(4/3)]}
=-2/x^(2/3)y^(2/3)
=-2x^(-2/3)y^(-2/3)
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