Question

(x-y+z)(-x+y+z)=[z+( )][（ ）-（ ）]=z²-（ ）平方

Answer 1

(x-y+z)(-x+y+z)=[z+(x-y )][（z ）-（x-y ）]=z²-（x-y ）平方

Answer 2

(x-y+z)(-x+y+z)=[z+(x-y )][（z ）-（ x-y）]=z²-（x-y )²

Answer 3

同意一楼。