化简√1-cosα/1+cosα+√1+cosα/1-cosα （π<α<3π/2）
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π<α<3π/2
sinα<弊皮0
cosα<0
√1-cosα/1+cosα+√1+cosα/1-cosα
=√(1-cosα)^2/(1-cosα)(1+cosα)+√(1+cosα)^2/滚卜肆(1-cosα)(1+cosα)
=√大轿(1-cosα)^2/(1-cos^2α)+√(1+cosα)^2/(1-cos^2α)
=√(1-cosα)^2/sin^2α+√(1+cosα)^2/sin^2α
=(1-cosα)/(-sinα)+(1+cosα)/(-sinα)
=-2/sinα
sinα<弊皮0
cosα<0
√1-cosα/1+cosα+√1+cosα/1-cosα
=√(1-cosα)^2/(1-cosα)(1+cosα)+√(1+cosα)^2/滚卜肆(1-cosα)(1+cosα)
=√大轿(1-cosα)^2/(1-cos^2α)+√(1+cosα)^2/(1-cos^2α)
=√(1-cosα)^2/sin^2α+√(1+cosα)^2/sin^2α
=(1-cosα)/(-sinα)+(1+cosα)/(-sinα)
=-2/sinα
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