Question

通分：（1）x/x²+2xy+y²与y/x+y (2）x+4/x²+4x与x-5/x(x-5)-2(x-5)

快速回答会被采纳哦！ 但是要正确的答案。

Answer 1

通分：（1）x/x²+2xy+y²与y/x+y
x/x²+2xy+y²=x/(x+y)²
y/x+y =[y(x+y)]/(x+y)²

(2）x+4/x²+4x与x-5/x(x-5)-2(x-5)
∵x+4/x²+4x=(x+4)/[x(x+4)]=1/x
x-5/x(x-5)-2(x-5)=(x-5)/[(x-5)(x-2)]=1/(x-2)

∴x+4/x²+4x=1/x=(X-2)/[x(x-2)]
x-5/x(x-5)-2(x-5)=1/(x-2)=x/[x(x-2)]

Answer 2

1 x/(x+y)^2 (y(x+y))/(x+y)^2
2 ((x+4)(x-5)(x-2))/((x(x+4)(x-2)(x-5)) (x(x-5)(X+4))/((x(x+4)(x-2)(x-5))