4个回答
2012-02-19 · 知道合伙人教育行家
关注
展开全部
(m+2)/(2m-4) ÷ [(m+2)-(m+2)/(m-2)]
= (m+2)/[2(m-2)] ÷ [(m+2)-(m+2)/(m-2)]
= (m+2)/[2(m-2)] ÷ (m+2) - (m+2)/[2(m-2)] ÷ (m+2)/(m-2)
= 1/[2(m-2)] - (m+2)/[2(m-2)] × (m-2)/(m+2)
= 1/[2(m-2)] -1/2
= [1-(m-2)]/[2(m-2)]
= (3-m) / [2(m-2)]
= (m+2)/[2(m-2)] ÷ [(m+2)-(m+2)/(m-2)]
= (m+2)/[2(m-2)] ÷ (m+2) - (m+2)/[2(m-2)] ÷ (m+2)/(m-2)
= 1/[2(m-2)] - (m+2)/[2(m-2)] × (m-2)/(m+2)
= 1/[2(m-2)] -1/2
= [1-(m-2)]/[2(m-2)]
= (3-m) / [2(m-2)]
追问
可参考答案的得数是1/m-m
追答
【 如果题目是: m + 2/(2m) - 4÷(m + 2 - m + 2/m - 2) 】
m + 2/(2m) - 4÷(m + 2 - m + 2/m - 2)
= m + 1/m - 4÷(m-m + 2- 2 + 2/m)
= m + 1/m - 4÷(2/m)
= m + 1/m - 4 × m/2
= m + 1/m - 2m
= 1/m - m
展开全部
m+2/2m-4÷(m+2-m+2/m-2)
=(m+2)/(2m-4)÷[(m+2)(m-2)/(m-2)+2/(m-2)]
=(m+2)/2(m-2)÷[(m²-4+2)/(m-2)]
=(m+2)/2(m-2)x(m-2)/(m²-2)
=(m+2)/2(m²-2)
=(m+2)/(2m-4)÷[(m+2)(m-2)/(m-2)+2/(m-2)]
=(m+2)/2(m-2)÷[(m²-4+2)/(m-2)]
=(m+2)/2(m-2)x(m-2)/(m²-2)
=(m+2)/2(m²-2)
追问
可参考答案的得数是1/m-m
追答
m+2/2m-4÷(m+2-m+2/m-2)
=m+1/m-4÷(2/m)
=m+1/m-2m
=1/m-m
主要是题目不清楚 不知道到底括号括在哪里
现在应该没错了
祝学习进步,望采纳~~
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
m+2/2m-4÷(m+2-m+2/m-2)
=m+1/m-4÷(2/m)
=m+1/m-2m
=1/m-m
=m+1/m-4÷(2/m)
=m+1/m-2m
=1/m-m
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
m+2/2m-4÷(m+2-m+2/m-2)
=m+1/m-2m
=1/m-m
=m+1/m-2m
=1/m-m
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询