2sin50°+sin80°（1+√3tan10°）/√(1+sin100°) 求值 10
展开全部
2sin50°+sin80°（1+√3tan10°）/√(1+sin100°)
=2sin50°+sin80°(1+sin60°sin10°/cos60°cos10°)/√(1+2sin50°cos50°)
=2sin50°+sin80°(cos60°cos10°+sin60°sin10°)/[cos60°cos10°√(1+2sin50°cos50°)]
=2sin50°+sin80°cos50°/[cos60°cos10°(sin50°+cos50°)
=2sin50°+2cos50°/(sin50°+cos50°)
=2
=2sin50°+sin80°(1+sin60°sin10°/cos60°cos10°)/√(1+2sin50°cos50°)
=2sin50°+sin80°(cos60°cos10°+sin60°sin10°)/[cos60°cos10°√(1+2sin50°cos50°)]
=2sin50°+sin80°cos50°/[cos60°cos10°(sin50°+cos50°)
=2sin50°+2cos50°/(sin50°+cos50°)
=2
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
