求不定积分(x^4)*sinx
1个回答
展开全部
∫x^4*sin(x)dx
=-∫x^4dcos(x)
=-cos(x)x^4+∫cos(x)dx^4
=-cos(x)x^4+∫4x³dsin(x)
=-cos(x)x^4+4x³sin(x)-∫sin(x)d(4x³)
=-cos(x)x^4+4x³sin(x)+∫12x²dcos(x)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-∫cos(x)d(12x²)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-∫24xdsin(x)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-24xsin(x)+24∫sin(x)dx
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-24xsin(x)-24cos(x)+C
=4x(x²-6)sin(x)-(x^4-12x²+24)cos(x)+C
=-∫x^4dcos(x)
=-cos(x)x^4+∫cos(x)dx^4
=-cos(x)x^4+∫4x³dsin(x)
=-cos(x)x^4+4x³sin(x)-∫sin(x)d(4x³)
=-cos(x)x^4+4x³sin(x)+∫12x²dcos(x)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-∫cos(x)d(12x²)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-∫24xdsin(x)
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-24xsin(x)+24∫sin(x)dx
=-cos(x)x^4+4x³sin(x)+12x²cos(x)-24xsin(x)-24cos(x)+C
=4x(x²-6)sin(x)-(x^4-12x²+24)cos(x)+C
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询