初二数学题,第二问。
2016-11-12
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证明
(10n+5)*(10n+5)
=10n(10n+5)+5(10n+5)
=100n²+50n+50n+25
=100n²+100n+25
=n*(n+1)*100+25
(10n+5)*(10n+5)
=10n(10n+5)+5(10n+5)
=100n²+50n+50n+25
=100n²+100n+25
=n*(n+1)*100+25
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