Question

用C++写一个程序，输入两个整型a，b和一个字符 当输入A时输出a+b的值，输入B时输出a-b的值 输入C时输出NO

是用键盘输入a,b和字符
初学者 请用较简单的C语言
键盘输入a,b的整数和字符A或B或C

Answer 1

#include<iostream>

using namespace std;

void main(){
int a,b;
char c;

cin>>a>>b>>c;
if(c=='A')
cout<<a+b;
else if(c=='B')
cout<<a-b;
else if(c=='C')
cout<<"NO";
else
cout<<"error!";
}

Answer 2

#include<stdio.h>
#include<string.h>
void main()
{
int a,b;
char str;
printf("请输入整型a：");
scanf("%d",&a);
printf("请输入整型b：");
scanf("%d",&b);
printf("请输入一个字符str：");
scanf("%s",&str);
if(str=='A')
printf("%d\n",a+b);
else
if(str=='B')
printf("%d\n",a-b);
else
if(str=='C')
printf("NO\n");
else
printf("ERROR!\n");

}

Answer 3

我能想到的最简单的程序哈：
#include<stdio.h>
void main()
{
int n,m,j;
char i;
scanf("%d%d\n",&n,&m);
printf("please input two number n,m and input a,b or c:\n");
printf("a is n+m\nb is n-m\nc is error\n");
scan("%c",i)
swicth(i)
case a: j=n+m,printf("%d"j);break;
case b: j=n-m,printf("%d"j);break;
case c: printf("no");break;

}
我个人习惯了C，在C的环境下是兼容C++的。

Answer 4

#include<stdio.h>
void main()
{
int a,b;
char k;
{printf("请输入a=");}
scanf("%d",&a);
#include<stdio.h>
void main()
{
int a,b;
char k;
{printf("请输入a=");}
scanf("%d",&a);
{printf("请输入b=");}
scanf("%d",&b);
{printf("请输入A或B或C\n");}
scanf(" %c",&k); \*%c前有一个空格*\
if(k=='A') printf("%d\n",a+b);
if(k=='B') printf("%d\n",a-b);
if(k=='C') printf("NO\n");
}

Answer 5

#include <stdio.h>
int main()
{
int a,b;
char c;
scanf("%d%d%c",&a,&b,&c);
if(c=='A')
printf("%d\n",a+b);
else if( c =='B')
printf("%d"\n",a-b);
else if(c == 'C')
printf("NO\n");
}