Question

a的4次方+a的2次方b的2次方+b的4次方

初一因式分解

Answer 1

a的隐滑4次毕举方+a的2次方b的2次方+b的4次方
=(a²+b²)²-(ab)²
=(a²手携碧+b²+ab)(a²+b²-ab)

Answer 2

=a^4+2a^2b^2-a^2b^2+b^4
=(a^4+2a^2b^2+b^4)-(ab)^2
=(a^2+b^2)^2-(ab)^2
=(a^2+ab+b^2)(a^2-ab+b^2)