在用quartusII验证vhdl程序时发现的错误,是书上的例子.
libraryieee;useieee.std_logic_1164.all;useieee.std_logic_arith.all;useieee.std_logic_...
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_arith.all;
use ieee.std_logic_unsigned.all;
entity adder is
port( in1: in std_logic;
in2: in std_logic;
cntl: bit;
pout: out bit_vector);
end adder;
architecture func of adder is
begin
process(cntl)
begin
if(cntl='1') then pout<=in1+in2;
end if;
end process;
end func;
提示错误:Error (10327): VHDL error at adder.vhd(16): can't determine definition of operator ""+"" -- found 0 possible definitions 展开
use ieee.std_logic_1164.all;
use ieee.std_logic_arith.all;
use ieee.std_logic_unsigned.all;
entity adder is
port( in1: in std_logic;
in2: in std_logic;
cntl: bit;
pout: out bit_vector);
end adder;
architecture func of adder is
begin
process(cntl)
begin
if(cntl='1') then pout<=in1+in2;
end if;
end process;
end func;
提示错误:Error (10327): VHDL error at adder.vhd(16): can't determine definition of operator ""+"" -- found 0 possible definitions 展开
2个回答
展开全部
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_arith.all;
use ieee.std_logic_unsigned.all;
entity adder is
port( in1: in std_logic;
in2: in std_logic;
cntl: std_logic;
pout: out std_logic);
end adder;
architecture func of adder is
begin
process(cntl)
begin
if(cntl='1') then pout<=in1 and in2;
end if;
end process;
end func;
帮你改了下 应该可以用了
use ieee.std_logic_1164.all;
use ieee.std_logic_arith.all;
use ieee.std_logic_unsigned.all;
entity adder is
port( in1: in std_logic;
in2: in std_logic;
cntl: std_logic;
pout: out std_logic);
end adder;
architecture func of adder is
begin
process(cntl)
begin
if(cntl='1') then pout<=in1 and in2;
end if;
end process;
end func;
帮你改了下 应该可以用了
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询