数学，先化简，再求值
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(x^2+2x+1)/(x+2)-(x^2-1)/(x-1)-1/(x+2)
=[(x^2+2x+1)/(x+2)-1/(x+2)]-(x+1)(x-1)/(x-1)
=(x^2+2x+1-1)/(x+2)-(x+1)
=(x^2+2x)/(x+2)-(x+1)
=x(x+2)/(x+2)-(x+1)
=x-(x+1)
=x-x-1
=-1
=[(x^2+2x+1)/(x+2)-1/(x+2)]-(x+1)(x-1)/(x-1)
=(x^2+2x+1-1)/(x+2)-(x+1)
=(x^2+2x)/(x+2)-(x+1)
=x(x+2)/(x+2)-(x+1)
=x-(x+1)
=x-x-1
=-1
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