Question

C语言 求高手 题目是 1-1/2+1/3-1/4+1/5-1/6+1/7……+1/2n-1 怎么做啊？我的这个程序哪有问题？

#include <stdio.h>
int main()
{
int i,j,s=1,n;
scanf("%d",&n);
if(n>=2)
{
for(j=2;j<=2;j++)
i=-1/(2*j-2)+1/(2*j-1);
s+=i;
}
printf("%d\n",s);
return 0;
}

Answer 1

一楼的肯定是不对的
#include <stdio.h>
main()
{
double i,n,s1=0,s2=0,sum;
scanf("%lf",&n); /* 输入n的值*/
for(i=1;i<=n;i++)
s1+=1/(2*i-1); /* 计算正数的和*/
for(i=2;i<=n;i++)
s2+=-1/(2*i-2); /* 计算负数的和*/
printf("%lf\n",s1+s2); /* 计算所有分数的和*/
}

Answer 2

变量的定义有些问题
#include <stdio.h>
int main()
{
int j,n;
double s = 1.0,i;
scanf("%d",&n);
if(n>=2)
{
for(j=2;j<=n;j++)
i=-1.0/(2*j-2)+1.0/(2*j-1);
s+=i;
}
printf("%lf\n",s);
return 0;
}

Answer 3

#include <stdio.h>
int main()
{
double num1=0,num2=1,temp1=1;

printf("please input the num!");

while (1)
{
scanf("%d",&num1);

if(num1 < 0)
{
printf("Please input the number of greater than zero!\n");
}
else
if((num1 == 0) || (num1 == 1))
{
num1 = 1;
printf("The answer is:%d\n",num1);
return 0;
}
else
{
continure;
}
}

for(num2;num2<2*num1 - 1;num2++)
{
if(num%2 == 0)
{
temp1 -= (1/num2);
}
else
{
temp1 += (1/num2);
}
}

printf("The answer is :%d\n",temp1);
return 0;
}

没编译器 好久没用了 应该是这样, 错了的话 可以看看思路