Question

#include <stdio.h> int main() { int n=0; while (n++<=2); printf ("%d",n); return 0; }

运行结果为什么是4

Answer 1

n=0,n++=0<=2, n=1;
n++=1<=2, n=2;
n++=2<=2, n=3;
n++=3>2退出循环，此时n=4
希望你能够理解

Answer 2

n=0,<=2, n++ = 1;
1<=2,n++ = 2;
2<=2,n++=3;
3<=2 (跳出)，n++ =4;
n++ <=2 这句判断完后，n 就自加

如果是(++n<=2)那就是3