Question

把极坐标方程ρcos（θ -π/6)=1化为直角坐标方程式?

Answer 1

ρcos（θ -π/6)=1
ρcosθ cosπ/6+ρsinθ sinπ/6=1
√3/2x+y/2=1
√3x+y-2=0

追问

√3x还需要继续化简吗

Answer 2

ρcos（θ -π/6)
=ρ*（cosθcosπ/6+sinθsinπ/6）
=√3/2ρcosθ+1/2ρsinθ

即√3/2x+1/2y=1