一二两题,求过程
1个回答
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1.1)
J dω/dt = M
dω/dt = (mgl/2) / (ml^2/3) = 3g/2l
a = l/2 * dω/dt = 3g/4
1.2)
E = Jω^2/2 = mgl/2
ω^2 = 3g/2l
ω = sqrt(3g/2l)
2
dω/dt = 1000*2π/60 / 5 = 20π/3
F(l1+l2)/l1 * R = J dω/dt
1.25F/0.5 * R = mR^2 * 20π/3
F = mR * 20π/3 * 0.5/1.25 = 40π = 125.7 [N]
J dω/dt = M
dω/dt = (mgl/2) / (ml^2/3) = 3g/2l
a = l/2 * dω/dt = 3g/4
1.2)
E = Jω^2/2 = mgl/2
ω^2 = 3g/2l
ω = sqrt(3g/2l)
2
dω/dt = 1000*2π/60 / 5 = 20π/3
F(l1+l2)/l1 * R = J dω/dt
1.25F/0.5 * R = mR^2 * 20π/3
F = mR * 20π/3 * 0.5/1.25 = 40π = 125.7 [N]
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